Implement Integer.parseInt from scratch

Question

Anonym · Accepted Answer

to study for this interview I suggest rewriting all of the basic Java methods ;)

not really! · Answer

can't u just parse char by char and use a bunch of shift operators and since ur just using charAt(i) to pick up a character u can use the same i and just raise it to the power of 10 and just or it with some bytes

Seluj · Answer

public static int parseInt(String stringToConvert)
	{
		int i =0,num=0;
		int isNeg = 1;
		int length = stringToConvert.length();
		
		if(stringToConvert.charAt(0) =='-')
		{
			isNeg=-1;
			i=1;
		}
		
		while(i

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